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Sagot :
Answer:
3
Step-by-step explanation:
2k+1 = 3k -2
k =3
every child has a 1 mom
f 7 = 3 f7= -6 this is imposible
[tex]\sf \boxed{\bold{k = 3}}[/tex]
Explanation:
If the first values of the two ordered pairs are the same, the relation is not a function.
Solve:
2k + 1 = 3k -2
2k - 3k = -2-1
-k = -3
k = 3
When k = 3, for the relation R= {(2k+1, 3), (3k-2, -6)} will not be a function.
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