Answered

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For what value of k will the relation R= {(2k+1, 3), (3k-2, -6)} not be a function?

Sagot :

ngulungulukante

Answer:

3

Step-by-step explanation:

2k+1 = 3k -2

k =3

every child has a 1 mom

f 7 = 3 f7= -6 this is imposible

fieryanswererft

[tex]\sf \boxed{\bold{k = 3}}[/tex]

Explanation:

If the first values of the two ordered pairs are the same, the relation is not a function.

Solve:

2k + 1 = 3k -2

2k - 3k = -2-1

-k = -3

k = 3

When k = 3, for the relation R= {(2k+1, 3), (3k-2, -6)} will not be a function.

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