Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
The height of the triangle is 8root3 meters.
We have given that,
A tree breaks due to a storm and the broken part bends,
So that the top of the tree touches the ground making an angle of 60 degrees with the ground.
The distance between the feet of the tree to the point where the top touches the ground is 16m.
Let the Height of the Tree =AB+AD
and given that BD=8 m
Now, when it breaks a part of it will remain perpendicular to the ground (AB) and the remaining part (AD) will make an angle of 30 degrees.
Now, in △ABD
cos(30)=BD/AD=BD=root3AD/2
AD=2(8)/root3
also in the same triangle
[tex]tan(30)=AB/BD\implies 8/\sqrt{3}[/tex]
What is the height of the triangle?
Height of the tree=AB+AD
[tex]=\frac{16}{\sqrt{3} }+\frac{8}{\sqrt{3} } }[/tex]
[tex]=\frac{24}{\sqrt{3} } \\=8\sqrt{3}m[/tex]
Therefore the height of the triangle is 8root3.
To learn more about the height visit:
https://brainly.com/question/12903285
#SPJ1
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
