Answered

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A particle is moving along the x-axis so that its position at any time t is greater than and equal to 0 is given by x(t)=2te^-t?

A) Find v(t).

B) Find a(t).

C) At t=0, is the particle slowing down or speeding up? Explain.

D) At what time(s), if any, does the particle change directions? Justify your answer.


Any help would be GREATLY appreciated! Thank you!!!

Sagot :

for speed you can differentiate the equation, for acceleration you can again differentiate the equation .
at t=0 the particle is slowing down , when you get equation for velocity put t=0 then only -1 is left
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