ashleymariefaye9
Answered

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A total of $8000 is invested: part at 6% and the remainder at 10 %. How much is invested at each rate if the annual interest is $750?​

Sagot :

22emmanuelwright

Answer: $400 was invested

Step-by-step explanation: Based on the scenario in the question, our calculation goes thus:0.11x + 0.06(8000 - x) = 5000.11x + 480 - 0.06x = 5000.11x - 0.06x = 500 - 4800.05x = 20x = 20/0.05x = 400

$400 was invested at 11% Also, 8000 - 400 = 7600 invested at 6%


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