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Simplify the square root of (x^2 -6x+ 9) if x<3

Sagot :

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's evaluate ~

[tex]\qquad \sf  \dashrightarrow \: \sqrt{{x}^{2} - 6x + 9 }[/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{{x}^{2} - 3x - 3x+ 9 }[/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{{x(}^{} x- 3) - 3(x - 3) }[/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{( x- 3) (x - 3) }[/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{( x- 3) {}^{2} }[/tex]

[tex]\qquad \sf  \dashrightarrow \: {( x- 3) {}^{} }[/tex]

I hope you understood the procedure ~ let me know if you have doubts ~

Answered by James ~ ( Teeny fr )

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