paynelove19
Answered

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Given the formula, find the first five terms and the 10th term of each
sequence.
a n = 8 – 5n
My attempt:
a1 = 8(5)5 =a1 =5
a2=8(5)6-5=10
a3=8(5)7-5=15
a4=8(5)8-5=20
a5=8(5)9-5=25
a10=8(5)10-5=a1050?

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's calculate the Given terms ~

[tex] \textbf{1st Term :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_1 = 8 - 5(1)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_1 = 8 - 5[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_1 = 3[/tex]

[tex] \textbf{2nd Term :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_2 = 8 - 5(2)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_2 = 8 - 10[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_2 = - 2[/tex]

[tex] \textbf{3rd Term :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_3 = 8 - 5(3)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_3 = 8 - 15[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_3 = - 7[/tex]

[tex] \textbf{4th Term : } [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_4 = 8 - 5(4)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_4 = 8 -20[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_4 = - 12[/tex]

[tex] \textbf{5th Term :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_5 = 8 - 5(5)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_5 = 8 - 25[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_5 = -17[/tex]

[tex] \textbf{10th Term :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_{10} = 8 - 5(10)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_{10} = 8 - 50[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_{10} = - 42[/tex]
  • a_n=8-5n

#1

  • a_1=8-5(1)=8-5=3

#2

  • a_2=8-5(2)=8-10=-2

#3

  • a_3=8-5(3)=8-15=-7

#4

  • a_4=8-5(4)=8-20=-12

#5

  • a_5=8-5(5)=8-25=-17

#10

  • a_10=8-5(10)=8-50=-42
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