bernicemampiah
Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

1. 5.8g of lithium bromide is dissolved in water to make a 270 L solution. Express the concentration in ppm.

Sagot :

Medunno13
Parts per million = (moles of solute)/(liters of solution) * 10^6

First, we need to find the number of moles of the solute, lithium bromide. Lithium bromide has a formula of LiBr, so we can conclude its gram-formula mass is 6.94+79.904=86.844 g/mol. This means that there are 5.8/86.844 = 0.0667864216 moles of lithium bromide.

So, the concentration in ppm is (0.0667864216)/(270) * 10^6 = 250 ppm (to 2 s.f.)
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.