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Sagot :
slope=-9/12 = -3/4
y=mx+b y=-3/4x+b
3=-3/4(-6)+b
b=3+9/2=7.5
Equation is y=-0.75x+7.5
y=mx+b y=-3/4x+b
3=-3/4(-6)+b
b=3+9/2=7.5
Equation is y=-0.75x+7.5
Answer:
[tex]y = -\frac{3}{4}x-\frac{3}{2}[/tex]
Step-by-step explanation:
First, calculate the slope of the line:
[tex]m = \frac{y_2-y_1}{x_2-x_1}\\m = \frac{(-6) - 3}{6 - (-6)}\\m = \frac{-9}{12}\\m = \frac{-3}{4}[/tex]
Next, calculate the y-intercept:
Choose any point on the line.
[tex](-6,3)[/tex]
Solve for [tex]b[/tex].
[tex]y = mx + b\\b = y - (mx)\\b = 3 - (\frac{-3}{4} * -6)\\b = 3 - \frac{9}{2}\\b = \frac{-3}{2}[/tex]
Finally, create the equation:
[tex]y = -\frac{3}{4}x-\frac{3}{2}[/tex]
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