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Sagot :
Answer:
x = 4, y = 2
Step-by-step explanation:
Solve the following system:
{y + x = 6 | (equation 1)
-5 y + 3 x = 2 | (equation 2)
Swap equation 1 with equation 2:
{3 x - 5 y = 2 | (equation 1)
x + y = 6 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 x - 5 y = 2 | (equation 1)
0 x + (8 y)/3 = 16/3 | (equation 2)
Multiply equation 2 by 3/8:
{3 x - 5 y = 2 | (equation 1)
0 x + y = 2 | (equation 2)
Add 5 × (equation 2) to equation 1:
{3 x + 0 y = 12 | (equation 1)
0 x + y = 2 | (equation 2)
Divide equation 1 by 3:
{x + 0 y = 4 | (equation 1)
0 x + y = 2 | (equation 2)
Collect results:
Answer: {x = 4, y = 2
Step-by-step explanation:
C.) (x,y) = (4,2)
Showing Work:
x+y=6
3x-5y=2
Minus y on both sides
x=6-y
3x-5y=2
Substitute the value of x (which is 6-y) into the second equation
3(6-y)-5y=2
Which ends up being 2
So y=2
Then take the value of y (which is 2) and substitute it into the first equation
x=6-2
x=4
So, like I said,
(x,y) = (4,2)
D.) (x,y) = (9/2, 7)
4x-y=11
6x-2y=13
Then it become:
y=-11+4x
6x-2y=13
Substitute the value of y
6x-2(-11+4x)=13
Which ends up being:
x = 9/2
Then to solve for y just substitute value of x
y= -11+4×9/2
Which is
y=7
So,
(x,y) = (9/2, 7)
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