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Sagot :
The height of the tree is 4.15m
We are given that
Height of Joshua, h=1.85 m
Length of tree's shadow, L=39.55 m
Distance between the tree and Joshua=35.4 m
We have to find the height of the tree.
BC=35.4 m
BD=39.55m
What is the height?
CD=BD-BC
CD=-35.4 m=4.15 m
EC=1.45 m
All right triangles are similar. When two triangles are similar then the ratio of their corresponding sides is equal.
[tex]\triangle ABD=\triangle ECD[/tex]
[tex]\frac{AB}{EC}=\frac{BD}{CD}[/tex]
Substitute the values
[tex]\frac{AB}{1.45}=\frac{39.55\times 1.45}{4.15} \\\\AB=20.39[/tex]
Hence, the height of the tree=20.39 m
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