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Sagot :
Hey ! there
Answer:
- First number = 1
- Second number = 5
Step-by-step explanation:
In the question we are given that sum of two numbers is 6 , second number is three more than twice the first number .And We are asked to find the two numbers .
We are solving this question by assuming ,
- First number as x
- Second number as 2x + 3 ( Because in the question it is given that the second number is three more than twice the first number )
Solution : -
As question says that sum of two numbers is 6 that is :
- First number + Second number = 6
Now , substituting value of first and second number which we have assumed above ,
[tex] \longmapsto \qquad \: x +2x + 3 = 6[/tex]
Step 1 : Adding like terms on left side :
[tex]\longmapsto \qquad \:3x + 3 = 6[/tex]
Step 2 : Subtracting with 3 on both sides :
[tex]\longmapsto \qquad \:3x + \cancel{3 }- \cancel{3 }= 6 - 3[/tex]
On further calculating, We have :
[tex]\longmapsto \qquad \:3x = 3[/tex]
Step 3 : Dividing with 3 on both sides :
[tex]\longmapsto \qquad \: \dfrac{ \cancel{3}x}{ \cancel{3} }= \cancel{ \dfrac{3}{3} }[/tex]
On calculating further, We get :
[tex]\longmapsto \qquad \: \blue{\underline{\boxed{ \pink{\sf{x = 1}}}}}[/tex]
We know that ,
- x is our first number
Therefore , first number is ❝ 1 ❞ .
And ,
- 2x + 3 is our second number . So ,
- 2 ( 1 ) + 3
- 2 + 3
- 5
Therefore , second number is ❝ 5 ❞ .
Verifying : -
Now we are verifying our answer by adding both the numbers and equating it with 6 as it's given in question that sum of both the numbers is equal to 6 .
- First Number + Second Number = 6
- 1 + 5 = 6
- 6 = 6
- L.H.S = R.H.S
- Hence, Verified .
Therefore, our answer is correct .
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