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what is the solution for the equation -15=5(3y-10)-5y

Sagot :

charliethebest2002

Answer:

  • [tex]\Large\boxed{\sf{y=\dfrac{7}{2} }}[/tex]

Step-by-step explanation:

Isolate the variable of y from one side of the equation.

-14=5(3y-10)-5y

First, switch sides.

[tex]\sf{5\left(3y-10\right)-5y=-15}[/tex]

Use the distributive property.

DISTRIBUTIVE PROPERTY:

A(B-C)=AB-AC

5(3y-10)

Multiply by expand.

5*3y=15y

5*10=50

15y-50-5y

15y-5=10y

= 10y-50

10y-50=-15

Add by 50 from both sides.

10y-50+50=-15+50

Solve.

10y=35

Then, you divide by 10 from both sides.

10y/10=35/10

Solve.

Divide the numbers from left to right.

35/10=7/2

y=7/2

Divide is another option.

7/2=3.5

[tex]\Longrightarrow: \boxed{\sf{y=\dfrac{7}{2}}}[/tex]

  • Therefore, the correct answer is y=7/2.

I hope this helps. Let me know if you have any questions.

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