At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Find the equation of a line perpendicular to y=−6 that contains the point (1,3). Write the equation in slope-intercept form

Sagot :

Answer:

x=1

Step-by-step explanation:

Hi there!

We are given that a line is perpendicular to y = -6 and passes through the point (1, 3)

We want to write the equation of this line in slope-intercept form

Slope-intercept form is y=mx+b, where m is the slope and b is the value of y at the y intercept, hence the name

First, we need to find the slope (m) of the line

Remember that we were given that the line is perpendicular to y = -6

Perpendicular lines have slopes that multiply to get -1

The slope of y = -6 is 0; therefore, to find the slope of this line, we can do the following equation

0m=1

Divide both sides by 0

m = 1/0

This answer is undefined - therefore, the line has an undefined slope

If this is the case, then it means the line is a vertical line

A vertical line is written as x=k, where k is the value of x at the x intercept. It can't be written in slope-intercept form.

This value is also the value of x at every point that lies on such line - in this case, as given by the point (1, 3) , this value is 1

So substitute 1 as k.

x = 1

This is the line of the equation.

Hope this helps!