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[tex]\int\limits sec^{2}x[/tex] [tex]dx[/tex][tex]=[/tex]

(AP Calculus AB)

Sagot :

linandrew41

The problem wishes us to integrate [tex]sec^{2}(x)[/tex]

   -However, we know based on the derivation of tan (x)

         [tex]\frac{d}{dx}tan(x)=sec^{2} (x)[/tex]

Bascially integration is the reversal of the derivation:

Thus

   [tex]\int\limits^a_b {sec^{2}(x)} \, dx =tan(x) +C[/tex]

Since there are no bounds, we must add a constant 'C' as we don't know if there was an initial value

Hope that helps!

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