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Sagot :
The values of molarity and volumes for the given questions are 2,100 mL, 0.75 M, 0.1 M, 50,000 mL, 2.07 M and 1,200 mL respectively.
What is the relation between the molarity & volume of solution?
Relation between the molarity and volume of the solution will be shown by the following equation:
M₁V₁ = M₂V₂, where
M₁ & V₁ is the molarity and volume of one solution whereas M₂ & V₂ are the molarities and volume of the another solution.
- Required volume of water needed to add at 750 mL of a 2.8 M HCl solution to make a 1.0 M solution will be calculated by using the above formula:
V₂ = (750)(2.8) / (1) = 2,100 mL
- Required molarity of diluted solution obtained on adding 25 mL of water to 125 mL of a 0.15 M NaOH solution will be calculated by using the above formula:
M₂ = (0.15)(125) / (25) = 0.75 M
- Required molarity of diluted solution obtained on adding 100 mL of a 0.15 M NaOH solution until the final volume is 150 mL will be calculated by using the above formula:
M₂ = (100)(0.15) / (150) = 0.1 M
- Required volume of HCl of 0.05M HCl can be made by diluting 250 mL of 10 M HCl will be calculated by using the above formula:
V₂ = (10)(250) / (0.05) = 50,000 mL
- Molarity of the resultant solution is:
M₂ = (1.5)(345) / (250) = 2.07 M
- Required volume of water to add on KCl solution is:
V₂ = (2.4)(500) / (1) = 1,200 mL
Hence required values of molarity and volume are 2,100 mL, 0.75 M, 0.1 M, 50,000 mL, 2.07 M and 1,200 mL respectively.
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