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12. Linda walks through a road. If her walking speed increases from 1 m/s to 1.5 m/s, she will complete the walk 200 s earlier. Find the distance travelled by Linda.​

Sagot :

Answer:

600 meters

Step-by-step explanation:

Case 1 : Speed of 1 m/s

  • d = v * t
  • d = 1 * t
  • d = t       [Equation 1]

Case 2 : Speed of 1.5 m/s

  • d = v * t
  • d = 1.5 * (t - 200)
  • d = 1.5t - 300 [Equation 2]

As distance in both cases is the same, equate the values of d from both equations.

  • t = 1.5t - 300
  • 0.5t = 300
  • t = 300 * 2
  • t = 600 s

Now, put the value of t in Equation 1 to find d.

  • d = 600 meters
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