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Sagot :
- 2250g of water
- 281.25g of water
- 611g of propane
- 1350g of water
Calculation of quantity of substance in grams
- From the balanced equation for water formation: 2H2 + O2 ---> 2H2O
Molar mass of 2H2, O2 and 2H2O is 4g, 32g and 36 g per moles respectively.
That is , 4g of H2 = 36g of water
250g of H2 = xg of water
Make xg the subject of formula,
xg = 250× 36/4
xg = 9000/4
xg = 2250g of water
- From the balanced equation for water formation: 2H2 + O2 ---> 2H2O
Molar mass of 2H2, O2 and 2H2O is 4g, 32g and 36 g per moles respectively.
32g of oxygen = 36g of water
250g of oxygen = xg of water
Make xg the subject of formula,
xg = 250 × 36/32
xg = 9000/32
xg = 281.25g of water
- The balanced chemical equation for the combustion of propane is:
C3H8(g)+5O2(g)→3CO2(g)+4H2O(g).
Molar mass of propane and water is 44g and 72g per mole.
if 44g of propane = 72 g of water
xg of propane = 1000g of water
make xg the subject of formula,
xg = 44 × 1000/72
xg = 44000/72
xg = 611g of propane
- The electrolysis of water can be used to the form hydrogen gas. The balanced equation is listed below:
2 H2O → 2H2 + O2
Molar mass of 2H2O and 2H2 is 36g and 4g respectively.
If 36g of water = 4g of Hydrogen
xg of water = 150 g of hydrogen
Make xg the subject of formula,
xg = 36×150/4
xg = 5400/4
xg = 1350g of water
Learn more about combustion here:
https://brainly.com/question/25141046
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