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1. How much water could you get if you started with 250.0 grams of hydrogen?



2. How much water could you get if you started with 250.0 grams of oxygen?


3. How much propane would you need to produce 1000.0 grams of water?


4. How much of each reactant is needed to produce 150 grams of hydrogen gas?

Sagot :

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  1. 2250g of water
  2. 281.25g of water
  3. 611g of propane
  4. 1350g of water

Calculation of quantity of substance in grams

  • From the balanced equation for water formation: 2H2 + O2 ---> 2H2O

Molar mass of 2H2, O2 and 2H2O is 4g, 32g and 36 g per moles respectively.

That is , 4g of H2 = 36g of water

250g of H2 = xg of water

Make xg the subject of formula,

xg = 250× 36/4

xg = 9000/4

xg = 2250g of water

  • From the balanced equation for water formation: 2H2 + O2 ---> 2H2O

Molar mass of 2H2, O2 and 2H2O is 4g, 32g and 36 g per moles respectively.

32g of oxygen = 36g of water

250g of oxygen = xg of water

Make xg the subject of formula,

xg = 250 × 36/32

xg = 9000/32

xg = 281.25g of water

  • The balanced chemical equation for the combustion of propane is:

C3H8(g)+5O2(g)→3CO2(g)+4H2O(g).

Molar mass of propane and water is 44g and 72g per mole.

if 44g of propane = 72 g of water

xg of propane = 1000g of water

make xg the subject of formula,

xg = 44 × 1000/72

xg = 44000/72

xg = 611g of propane

  • The electrolysis of water can be used to the form hydrogen gas. The balanced equation is listed below:

2 H2O → 2H2 + O2

Molar mass of 2H2O and 2H2 is 36g and 4g respectively.

If 36g of water = 4g of Hydrogen

xg of water = 150 g of hydrogen

Make xg the subject of formula,

xg = 36×150/4

xg = 5400/4

xg = 1350g of water

Learn more about combustion here:

https://brainly.com/question/25141046

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