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Sagot :
given:
base= 25 mm
height= 28 mm
to find:
the volume of the square pyramid.
solution:
[tex]volume = {a}^{2} \frac{h}{3} [/tex]
[tex]v = {25}^{2} \frac{28}{3} [/tex]
[tex]v = 5833.33333 {mm}^{3} [/tex]
[tex]v = 5833.3 {mm}^{3} [/tex]
Given:-
- Base , (B) = 25 mm
- Height , (H) = 28 mm
To Find:-
- Volume of The Square Pyramid = ??
Solution:-
[tex] \\ \diamond{\underline{\underline{\sf {\;\; Calculating\; Volume\; of \; Pyramid :-}}}} \\ [/tex]
[tex] \\ \footnotesize{\underline {\boxed {\bf{Volume _{ \{ \red{pyramid} \} } \: = \: {a}^{2} \: \: \times \: \dfrac{h}{3} \: }}} }\; \red\bigstar \\ [/tex]
Where,
- » A denotes Base
- » H denotes Height
[tex] \\ \sf \implies \: Volume _{ \{ \red{pyramid} \} } \: = \: {a}^{2} \: \: \times \: \dfrac{h}{3} \: \\ [/tex]
[tex]\\ \sf \implies \: Volume _{ \{ \red{pyramid} \} } \: = \: {25}^{2} \: \: \times \: \dfrac{28}{3} \: \\ [/tex]
[tex]\\ \sf \implies \: Volume _{ \{ \red{pyramid} \} } \: = \: 233.3 \: {mm}^{3} \: \\ [/tex]
[tex] \\\implies{\underline{\boxed {\frak{ Volume _{ \{ \red{pyramid} \} } \: = \: 233.3 \: {mm}^{3} }}}}\purple \bigstar\\[/tex]
[tex] \\\qquad \rule{120pt}{3pt}\\[/tex]
Therefore , the volume of Square Pyramid is is 233.3 mm³.
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