Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:
C. The equation has two valid solutions
Step-by-step explanation:
A rational equation like this is often solved by "cross-multiplying" to eliminate the fractions. When we do that, we get ...
4(2x+10) = x(3x+1) . . . . . . . multiply both sides by (3x+1)(2x+10)
3x² -7x -40 = 0 . . . . . . . . . . rearrange to standard form
3x² -15x +8x -40 = 0 . . . . . . separate -7 into factors of 3(-40)
3x(x -5) +8(x -5) = 0 . . . . . factor pairs of terms
(3x +8)(x -5) = 0 . . . . . . . finish factoring
The zeros of these factors are not zeros of the original denominators, so neither of the solutions these give is extraneous.
3x +8 = 0 ⇒ x = -8/3
x -5 = 0 ⇒ x = 5
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.