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The half life of radium is 1690 years. if 80 grams are present now, how much will be present in 830 years

Sagot :

s2270595

Answer:

A(t) = amount remaining in t years

      = A0ekt, where A0 is the initial amount and k is a constant to                     be determined.  

Since A(1690) = (1/2)A0 and A0 = 80,

                we have 40 = 80e1690k

                1/2 = e1690k

                ln(1/2) = 1690k

                k = -0.0004

So, A(t) = 80e-0.0004t

Therefore, A(430) = 80e-0.0004(430)

                           = 80e-0.172

                           ≈ 67.4 g

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