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Sagot :
60 bottles required.
calculate the volume of both shapes
For hemispherical bowl:
[tex]\sf volume: \dfrac{2}{3} \pi r^3[/tex] [diameter: 30 cm, radius: 15 cm]
[tex]\rightarrow \sf volume: \dfrac{2}{3} \pi (15)^3[/tex]
[tex]\rightarrow \sf volume: 2250\pi \ cm^3[/tex]
For each cylindrical bottles:
[tex]\sf volume: \pi r^2h[/tex] ["r" is 2.5 cm, "h" is 6 cm]
[tex]\rightarrow \sf volume: \pi (2.5)^2(6)[/tex]
[tex]\rightarrow \sf volume: 37.5 \pi \ cm^3[/tex]
So number of required bottles:
- volume of hemisphere/volume of each cylindrical bottle
- 2250π/37.5π
- 60 bottles
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