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If p(x)=5(x²+1)+16 then what is p(11)?

Sagot :

Answer:

626

Step-by-step explanation:

  1. substitute whatever they put in the brackets into wherever X appears in the equation
  2. they put 11 in the brackets, so replace X in the equation with 11
  3. [tex]5({11}^{2} + 1) + 16[/tex]
  4. this is just 5 (121+1) + 16
  5. 5(122) + 16
  6. 610 + 16
  7. 626
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