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An apple is released from rest 500 m above the ground. Due to the combined forces of air resistance and gravity, it has a speed of 40 m s when it reaches the ground. What percentage of the initial mechanical energy of the apple-earth system was dissipated due to air resistance? take the potential energy of the apple-earth system to be zero when the apple reaches the ground.

Sagot :

batolisis

The percentage of the initial mechanical energy of the apple-earth system that was dissipated is : 84%

Determine the percentage of the initial mechanical energy dissipated

Given that

Potential energy = mgh = 0

                           = m* 9.81 * 500 = 0

                           = 4905 m J

Kinetic energy ( K ) = 1/2 mv²

                                 = 1/2 * m * 40²

                                 = 800 m

Next step : calculate the dissipated energy

dissipated energy = Potential energy - kinetic energy

                              = 4905 m - 800 m

                              = 4105 m

Final step : determine the percentage of the dissipated energy

= dissipated energy / potential energy

= 4105 m / 4905 m

= 84%

Hence we can conclude that The percentage of the initial mechanical energy of the apple-earth system that was dissipated is : 84%

Learn more about dissipated energy : https://brainly.com/question/13108225

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