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Sagot :
Answer:
[tex]\sf \tan(x)=\dfrac{4}{3}[/tex]
Step-by-step explanation:
Trigonometric ratios
[tex]\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}[/tex]
where:
- [tex]\theta[/tex] is the angle
- O is the side opposite the angle
- A is the side adjacent the angle
- H is the hypotenuse (side opposite the right angle)
From inspection of the diagram:
- [tex]\theta[/tex] = x
- O = 8
- A = 6
- H = 10
[tex]\implies \sf \tan(x)=\dfrac{8}{6}=\dfrac{4}{3}[/tex]
[tex]\\ \rm\Rrightarrow tanx=\dfrac{Perpendicular}{Base}[/tex]
- Perpendicular=8
- Base=6
[tex]\\ \rm\Rrightarrow tanx=\dfrac{8}{6}[/tex]
[tex]\\ \rm\Rrightarrow tanx=\dfrac{4}{3}[/tex]
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