Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

The heat Q required to raise the temperature of water varies jointly as the mass m of the water and the amount of temperature change T, and Q=20930 joules (J) when m=1kg and T=5 degrees C. Find m when Q=8372 J and T=10 degrees C

Sagot :

Answer:

m = 0.2 kg.

Step-by-step explanation:

Joint variation:

Q = kmT where k is a constant.

Subsituting the given values:

20930 = k*1*5

k = 20930 / 5 = 4186.

So the relation is:

Q = 4186mT

When Q = 8372 and T = 10:

8372 = 4186 * m * 10

m = 8372 / (4186*10)

m = 0.2 kg.

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.