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A ray of light in air strikes the surface of a liquid at an angle of 65 degrees with the normal. The refracted ray is at an angle of 42 degrees with the normal. What is the index of refraction of this liquid?

Sagot :

The index of refraction of this liquid will be 1.28. It is found as the ratio of the sin of the angle of incidence and the angle of reflection.

What is an index of refraction?

The refractive index of a substance is a dimensionless quantity that specifies how quickly light passes through it in optics.

The given data in the problem is;

Angle of incidence (i)= 65°

Angle of refraction(r) = 42°

The formula for the index of refraction is;

[tex]\rm n = \frac{sin \ i }{sin \ r} \\\\ \rm n = \frac{sin 65 ^0}{sin 42^0} \\\\ n=1.28[/tex]

Hence, the index of refraction of this liquid will be 1.28.

To learn more about the index of refraction, refer to the link;

https://brainly.com/question/23750645

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