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The number of electrons present in -2.8µC of excess electric charge is 1.75 × 10¹³ electrons
Calculating the number of electrons
From the question, we are to determine the number of electrons present in the given charge
The number of electrons can be determined by using the formula,
[tex]n = \frac{q}{e}[/tex]
Where n is the number of electrons
q is the magnitude of charge
and e is the charge of an electron (e = 1.6 × 10⁻¹⁹ C)
From the given information,
q = 2.8 μC = 2.8 × 10⁻⁶ C
Putting the parameters into the equation, we get
[tex]n = \frac{2.8 \times 10^{-6} }{1.6 \times 10^{-19} }[/tex]
n = 1.75 × 10¹³ electrons
Hence, the number of electrons present in -2.8µC of excess electric charge is 1.75 × 10¹³ electrons
Learn more on Calculating the number of electrons here: https://brainly.com/question/9509017
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