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Question 3
6 pts
A ball is thrown vertically upward with an initial velocity of 48 feet per
second and started from a height of 8 ft off the ground.
a. Write a vertical motion equation that models the situation.
b. How long will it take the ball to hit the ground? (round to the nearest
Hundredth)
c. How long will it take the ball to be 56 ft above the ground?
No answer text provided.

Question 3 6 Pts A Ball Is Thrown Vertically Upward With An Initial Velocity Of 48 Feet Per Second And Started From A Height Of 8 Ft Off The Ground A Write A Ve class=

Sagot :

(a) The vertical motion equation for the ball is h = 8 + 48t - 16t².

(b) The time for the ball to hit the ground is 3.15 s.

(c) The time for the ball to travel 56 ft above the ground is 0.79 s.

Vertical motion equation for the ball

The vertical motion equation for the ball is calculated as follows;

h = h₀ + vt - ¹/₂gt²

h = 8 + 48t - ¹/₂(32)t²

h = 8 + 48t - 16t²

Time for the ball to hit the ground

0 = 8 + 48t - 16t²

solve the above quadratic equation with formula method;

a = -16, b = 48, c = 8

t = 3.15 s

Time for the ball to be 56 ft above the ground

  • let upward motion be positive

h = 8 + 48t + 16t²

56 = 8 + 48t + 16t²

0 = -48 + 48t + 16t²

solve the above quadratic equation with formula method;

a = 16, b = 48, c = -48

t = 0.79 s

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