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Sagot :
Answer:
[tex]B.210\ cm^2[/tex]
Step-by-step explanation:
[tex]We\ are\ given,\\Length\ of\ the\ base=35\ cm\\Length\ of\ the\ perpendicular\ dropped\ to\ the\ base=12\ cm\\We\ know\ that,\\Area\ of\ triangle=\frac{bh}{2}\\ Here,\\Area\ of\ triangle=\frac{12*35}{2}=6*35=210\ cm^2[/tex]
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