At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

2. A light fixture contains 6 light bulbs. With normal use, each bulb has a 0.85
chance of lasting for at least 4 months. What is the theoretical probability that
all 6 bulbs will last for 4 months? Round to the nearest whole percent.


Sagot :

Using the binomial distribution, it is found that there is a 0.38 = 38% theoretical probability that all 6 bulbs will last for 4 months.

What is the binomial distribution formula?

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, we have that:

  • There are 6 bulbs, hence n = 6.
  • Each bulb has a 0.85 chance of lasting for at least 4 months, hence p = 0.85.

The probability that all 6 bulbs will last for 4 months is P(X = 6), hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} \approx 0.38[/tex]

More can be learned about the binomial distribution at https://brainly.com/question/24863377

#SPJ1

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.