Answered

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Please help me with this. I need to solve for x.
4ln(7x+3)+12=40

Sagot :

andytran027

Answer:

[tex]x=\frac{e^7-3}{7}[/tex]

Step-by-step explanation:

4* ln(7x+3) + 12 = 40

4* ln(7x+3) + 12 - 12 = 40 - 12

4* ln(7x+3) = 28

ln(7x+3) = 28/4

ln(7x+3) = 7

e^7 = (7x + 3)

e^7 - 3 = 7x

[tex]x=\frac{e^7-3}{7}[/tex]

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