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The fifth grade students participating in the math competition will be evenly divided into teams of 3 students each. How many students could be participating?
25
21
23
26


Sagot :

Answer:

21

Step-by-step explanation:

We know that the total number of students has to be divisible by 3. So to solve this specific problem, you can either use a guess and check system, prior knowledge, or by using a factoring method.

If we try to divide all four answer choices evenly by 3, only 21 leaves us with a whole number. Therefore, there could be 21 students participating.

25/3 = 8.33

21/3 = 7

23/3 = 7.667

26/3 = 8.667