Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Two coils connected in series have a resistance of 36 ohm and when connected in parallel have a resistance of 8ohm. Find resistance of each coil​

Sagot :

jcherry99

Answer:

Explanation:

Remark

Two resistances in series has the form of

Rs= C1 + C2

Two resistances is parallel has the form of

Rp = (C1 *C2)/(C1 + C2)

The plan is to first of all find C1*C2 and use this information and C1 + C2 to find the individual resistances.

Givens

Rs = 36 ohms

Rp = 8 ohms

Solution

Rp = C1 * C2/(C1 + C2)

Rp = 8 ohms

C1 + C2 = 36 ohms

8 =    C1*C2 / 36                          Multiply by 36

8* 36 = C1*C2

C1*C2 = 288

Use Rs to solve for C1

  • C1 + C2 = 36
  • C1 = 36 - C2

(36 - C2) * C2 = 288

36*C2 - C2^2 =288                    Multiply by - 1

-36C2 + C2^2 = -288                 Add 288 to both sides

C2^2 - 36C2 + 288= 0               Factor this equation

(C2 - 12)(C2 - 24)

C2 - 12 = 0

C2 = 12

C2 - 24 = 0

C2 = 24

C2 = 24 or

C2 = 12

C1 = 36 - C2

C1 = 36 - 24 = 12

C1 = 36 - 12  = 24

Answer

C1 = 12 ohms or 24 ohms

C2 = 24 ohms or 12 ohms

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.