sweheilendy058
Answered

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How many milliliters of this solution are required to prepare 1.00 L of 0.130 M K2Cr2O7 ?

How Many Milliliters Of This Solution Are Required To Prepare 100 L Of 0130 M K2Cr2O7 class=

Sagot :

mkmkaleb

Answer:

First you'll need to divide the mass of K2Cr2O7 by its molar mass and volume which should be easy but I'll do some of it to help you out

Explanation:

[tex]K_{2}Cr_{2}O_{7}[/tex]

[tex]2K = 39.098 = 2(39.098) = 78.196[/tex]

[tex]2Cr = 51.996 = 2(51.996) = 103.992[/tex]

and

[tex]7O = 15.999 = 7(15.999) = 111.993[/tex]

[tex]78.196 + 103.992 + 111.993 = 294.181[/tex]

so that's the mass of K2Cr2O7 and then you divide it by the molar mass and volume.

Hopefully you can do that on your own! Hope I helped a bit atleast and I have a good feeling about 0.438 but I don't want you to just guess

View image mkmkaleb
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