Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
(1) The number of moles of oxygen gas is 0.123 mole.
(2) The volume occupied by the nitrogen gas is 50.75 Liters.
(3) The pressure exerted by the CO2 gas is 28.7 atm
(4) The temperature of the Cl2 gas is -118.37⁰C
Number of moles of oxygen
The number of moles of oxygen occupied at the given condition is calculated as follows;
PV = nRT
n = PV/RT
where;
- T = 25ºC = 273 + 25 = 298K
- R is ideal gas constant = 0.08205 L.atm/mol.K
n = (2.5 x 1.2) / (0.08205 x 298)
n = 0.123 mol
Volume of the gas
PV = nRT
V = nRT/P
where;
- R = 62.36 L.mmHg/mol.K
V = (2 x 62.36 x 293) / (720)
V = 50.75 Liters
Pressure of the gas
PV = nRT
P = nRT/V
where;
- n is number of moles
Molar mass of CO2 = 44
n = 25/44 = 0.568
P = (0.568 x 0.08205 x 308)/(0.5)
P = 28.7 atm
Temperature of the gas
T = PV/nR
molar mass of Cl2 = 71 g
n = 5/71 = 0.07
T = (900 x 0.75)/(0.07 x 62.36)
T = 154.63 K
T = 154.63 - 273 = -118.37⁰C
Learn more about volume of gas here: https://brainly.com/question/25736513
#SPJ1
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.