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Suppose a vehicle begins at rest at t=0 and accelerates at a rate given by the equation a(t) = (15 m/s^) t . Assume nonuniform acceleration.

Find the velocity a 3 seconds.

Find the displacement at 3 seconds.

Must show work.

Sagot :

Answer:

See below

Explanation:

vf = vo +  a t

   = 0    + 15 t  * t

 vf = 15 t^2

      = 15 (3)^2 = 135 m/s

displacement

x = 1/2 a t^2   = 1/2  (15t) t^2

x = 1/2 (15 t^3)

   = 202.5 m

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