Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Using the relation between velocity, distance and time, it is found that:
- a) The canoe should be traveling at a rate of 37.5 km/h.
- b) The canoe traveled at a rate of 6.124 km/h.
What is the relation between velocity, distance and time?
Velocity is distance divided by time, hence:
[tex]v = \frac{d}{t}[/tex]
Item a:
1.5 km in 6 hours, with a velocity of vc - 6, in which vc is the velocity of the canoe and 6 km/h is the velocity of the current, so:
[tex]vc - 6 = \frac{1.5}{6}[/tex]
vc - 36 = 1.5
vc = 37.5.
The canoe should be traveling at a rate of 37.5 km/h.
Item b:
Upstream, the velocity is given by vc - 6, as it is against the stream, hence:
[tex]vc - 6 = \frac{1.5}{2t}[/tex]
[tex]t(vc - 6) = \frac{1.5}{2}[/tex]
[tex]t = \frac{1.5}{2vc - 12}[/tex]
Downstream, we have that:
[tex]vc + 6 = \frac{1.5}{2(\frac{1.5}{2vc - 12})}[/tex]
[tex]vc + 6 = \frac{1.5}{vc - 6}[/tex]
[tex]vc^2 - 36 = 1.5[/tex]
[tex]vc = \sqrt{37.5}[/tex]
vc = 6.124.
The canoe traveled at a rate of 6.124 km/h.
More can be learned about the relation between velocity, distance and time at https://brainly.com/question/24316569
#SPJ1
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
