Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

The freezing point of pure benzene (C₆H₆) is 5. 49 °C. The freezing point of a solution made using toluene (C₇H₈) in benzene is determined to be -13. 0 °C. What is the molality of the toluene? (Kf benzene = 5. 12 °C/m)

Sagot :

The molality of the toluene is 1.46 mol/kg.

What is molality?

The molality of a solution is its molal concentration. Molal concentration is denoted by m. It is the mol of solute dissolves in 1 Kg solvent.

The depression at freezing point is directly proportional to the molality of the solution. The equation we use for this type of problem is:

ΔT=iKm [tex]f_m[/tex]

Where,  ΔT [tex]f_m[/tex] is depression at freezing point, i is Van't hoff factor, m is molality and [tex]K_f[/tex] is the freezing point depression constant.

Toluene is a non-electrolyte and so the value of i for this is 1.

Depression at a freezing point is given as -13.[tex]0^0[/tex] and the [tex]K_f[/tex] is given as 5.12. So, we could calculate the molality of the solution using the equation written above.

Let's plug in the values in the equation:

ΔT=iKm[tex]f_m[/tex]

-7.51 =1 x5. 12 xm

m = [tex]\frac{7.51}{5. 12}[/tex]

m = 1.46 m

It means the molality of the solution is 1.46 mol/kg.

Hence, the molality of the solution is 1.46 mol/kg.

Learn more about the molality of the solution here:

https://brainly.com/question/12123356

#SPJ1