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The center of another circle is (-5,1) Its radius is √14 What is the equation of this circle?

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theleangreenbean

Equation of a Circle

Circular equations are typically organized like this:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

  • [tex](h,k)[/tex] is the center of the circle
  • [tex]r[/tex] is the radius of the circle

Solving the Question

We're given:

  • The center is (-5,1)
  • The radius is [tex]\sqrt{14}[/tex]

Plug the given information into the formula:

[tex](x-h)^2+(y-k)^2=r^2\\(x-(-5))^2+(y-1)^2=(\sqrt{14})^2\\(x+5)^2+(y-1)^2=14[/tex]

Answer

[tex](x+5)^2+(y-1)^2=14[/tex]

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