Answered

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A particular .55 m solution contains 1.7 g of salt what mass would be present in the same volume of a 3.20 m solution

Sagot :

Medunno13

Answer: 9.9 g

Explanation:

We can set up a proportion:

1.7/.55 = x/3.20

x = 9.9 g (to 2 s.f.)

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