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What are the minimum energies of the two oppositely directed gamma rays in a PET procedure?

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batolisis

The minimum energy of the two oppositely directed gamma rays in a PET procedure is : 0.51 MeV

What happens in a PET procedure ?

In a PET procedure when an electron and positron collide the energy equivalent of their individual masses are converted into gamma rays which will move in directions opposite to each other.

Given that an electron and a positron posses equal masses the minimum energy of the gamma ray will be 0.51MeV

Hence we can conclude that the minimum energy of the two oppositely directed gamma rays in a PET procedure is 0.51MeV.

Learn more about PET procedure :https://brainly.com/question/238772

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