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Sagot :
Answer:
A polyhedron with 6 faces and 8 vertices has 12 edges.
Step-by-step explanation:
Euler Formula is given in the problem:
- F + V = E + 2
We are told that the polyhedron has 6 faces (F = 6) and 8 vertices (V = 8). The only unknown variable in Euler's Formula now is E = number of edges.
Substitute the known variables into the formula and solve for E.
- 6 + 8 = E + 2
- 14 = E + 2
- 12 = E
- E = 12
A polyhedron with 6 faces and 8 vertices has 12 edges.
Given:
Number of faces = 6
Number of vertices = 8
Formula used:
Euler's formula:
F + V - E = 2
F = Number of Faces of Polyhedron
V = Number of Vertices of Polyhedron
E = Number of Edges of Polyhedron
Calculations:
Let the polyhedron have E edges,
6 + 8 - E = 2
14 - E = 2
E = 14 - 2
E = 12
Therefore:
The Polyhedron has 12 edges
Number of faces = 6
Number of vertices = 8
Formula used:
Euler's formula:
F + V - E = 2
F = Number of Faces of Polyhedron
V = Number of Vertices of Polyhedron
E = Number of Edges of Polyhedron
Calculations:
Let the polyhedron have E edges,
6 + 8 - E = 2
14 - E = 2
E = 14 - 2
E = 12
Therefore:
The Polyhedron has 12 edges
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