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Sagot :
Answer:
Option #4: [tex]4\left(x+8\right)-10\ge 42[/tex]
Step-by-step explanation:
[tex]4\left(x+8\right)-10\ge 42[/tex]
x ≥ 5
Answer:
4th option
Step-by-step explanation:
the inequality shows x ≥ 5
solving the inequalities
- 7(3x - 7) + 21 ≥ 50
- 21x + 49 + 21 ≥ 50
- 21x + 70 ≥ 50 ( subtract 70 from both sides )
- 21x ≥ - 20
divide both sides by - 21 reversing the symbol as a result of dividing by a negative quantity , then
x ≤ [tex]\frac{20}{21}[/tex] ← not the required solution
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- 4(- x + 8) - 10 ≤ 8
4x - 32 - 10 ≤ 8
4x - 42 ≤ 8 ( add 42 to both sides )
4x ≤ 50 ( divide both sides by 4 )
x ≤ 12.5 ← not the required solution
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- 7(3x - 7) + 21x ≥ - 50
- 21x + 49 + 21x ≥ - 50 ( subtract 49 from both sides )
0 ≥ - 99 ← not the required solution
-----------------------------------------------------
4(x + 8) - 10 ≥ 42
4x + 32 - 10 ≥ 42
4x + 22 ≥ 42 ( subtract 22 from both sides )
4x ≥ 20 ( divide both sides by 4 )
x ≥ 5 ← Required solution
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