Answer:
[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]
( 3 )
the given figure resembles a rectangle !
now ,
[tex]Area \: of \: rectangle = length \times breadth \\ \\ given \: - \: length = 12 \: ft \\ \therefore \:breadth = x \: ft \\ \\ Area = 108 \: ft {}^{2} \\ \\ \implies \: length \times breadth = 108 \: ft {}^{2} \\ \\ \implies \: x \times 12 = 108 \\ \\ \implies \: x = \cancel\frac{108}{12} \\ \\ \bold\red{\implies \: x = 9 \: ft}[/tex]
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( 4 )
the given figure resembles a parallelogram!
[tex]Area \: of \: parallelogram = height \times base \\ \\ \implies \: height = x \: cm\\ \\ \implies \: base = 16 \: cm \\ \\ \: Area \: = 96 \: cm {}^{2} \\ \\ \implies \: x \times 16 = 96 \\ \\ \implies \: x = \cancel\frac{96}{16} \\ \\ \bold\red{\implies \: x = 6 \: cm}[/tex]
hope helpful :D
[tex]\huge \underbrace \mathfrak \red{Answer}[/tex]
To find :-
To get the value of 'di in figure 3 and 4.
Figure 3
Solution :-
Area of rectangle = length × width
area = 108 ft², length = 12 ft, width = x
[tex]108 = 12 \times x \\ \frac{108}{12} = x \\ 9 = x[/tex]
[tex] \\ [/tex]
Figure 4
Solution :-
Area of parallelogram = base × height
Area = 96 cm², base = 16 cm, height = x
[tex]96 = 16 \times x \\ \frac{96}{16} = x \\ 6 = x[/tex]