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If the specific heat of a material is 0.416 J/(g°C) and sample absorbs 50 J when it is heated from 30°C to 50°C what is the mass of the sample?

Sagot :

The mass of the sample of the material is 0.1664 g.

What is specific heat?

The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.

By the formula of specific heat

[tex]Q = mc \Delta T[/tex]

Given, that the specific heat (c) of material is 0.416 J/gC

The difference in temperatures is 30°C to 50°C

The mass=?

Q = heat, 50 J

Putting the values in the equation

[tex]\rm 50\;J = m \times 0.416 J/g^\circ C \times (50 - 30)\\\\m = \dfrac{0.416 J/g^\circ C \times 20}{50} = 0.1664 g[/tex]

Thus, the mass of the samples is 0.166 g.

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