victoriaballou07
Answered

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At what input value will the function f(x)=[tex]\sqrt{-x}[/tex]-2+2 begin to have real outputs?

Sagot :

Answer:

x = -2

Step-by-step explanation:

Domain of definition

[tex]\sqrt{-x-2}[/tex]

=> -x - 2 >= 0

=> x <= -2

When x = -2 f(x) gets real outputs

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