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what is the equation of the line that passes through the point (3,6) and has a slope of -1/3


ASAP PLS

Sagot :

[tex]\Large\texttt{Answer\::}[/tex]

Please consult the "Calculations" section of this ans .

[tex]\Large\texttt{Calculations\::}[/tex]

The information we're given is below :

  • slope : -1/3
  • Point crossed by the line : (3, 6)

As per given information , we can do the following :

  • Write the line's equation in point slope form

Point - slope form looks like so :

y-y₁=m(x-x₁)

y-6=-1/3(x-3)

y-6=-1/3x+1

y=-1/3x+1+7

y=-1/3x+6

↑ [tex]\small\textsc{EQUATION OF THE LINE}[/tex]

[tex]\small\textit{hope\:helpful~}[/tex]

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