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What is the molarity of a solution that contains 20 grams of CaBr2
in 0.50 liter of solution?

Sagot :

Answer:

2 M

Explanation:

mole weight of CaBr2 = 40 + 2 * 79.9 = 199.8 gm

20 gm is then   20/199.8 =.1 mole

.1 mole / .50 liter = 2 M

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