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What is P(A, B, and C)? They are independent.

P(A) = .66

P(B) = .52

P(C) = .78


Sagot :

If each of A, B, and C are mutually independent, then

P(A and B and C) = P(A) P(B) P(C)

so that the probability of the three-way intersection is

P(A and B and C) = 0.66 × 0.52 × 0.78 = 0.267696 ≈ 0.27

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