Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

If 0.5 L of a gas is cooled from 22°C to 4°C, what is the new volume of the gas?
ОА
0.02 L
B
0.47 L
С
0.60 L
D
2.75 L

Sagot :

msakerj

Answer:

B

Explanation:

From charles' law,

[tex]v \alpha t[/tex]

where v is volume and t is absolute temperature

  • [tex] \frac{v1}{t1} = \frac{v2}{t2} [/tex]
  • [tex]v1 = 0.5l \\ t1 = (22 + 273 )k\\ t2 = (4 + 273)k \\ t1 = 295k \\ t2 = 277k \\ \frac{0.5}{295} = \frac{v2}{277} \\ v2 = 277 \times \frac{0.5}{295} = 0.47l[/tex]
  • Hence that's it
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.