Answered

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If 0.5 L of a gas is cooled from 22°C to 4°C, what is the new volume of the gas?
ОА
0.02 L
B
0.47 L
С
0.60 L
D
2.75 L

Sagot :

msakerj

Answer:

B

Explanation:

From charles' law,

[tex]v \alpha t[/tex]

where v is volume and t is absolute temperature

  • [tex] \frac{v1}{t1} = \frac{v2}{t2} [/tex]
  • [tex]v1 = 0.5l \\ t1 = (22 + 273 )k\\ t2 = (4 + 273)k \\ t1 = 295k \\ t2 = 277k \\ \frac{0.5}{295} = \frac{v2}{277} \\ v2 = 277 \times \frac{0.5}{295} = 0.47l[/tex]
  • Hence that's it
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